Dear VU (Virtual University of Pakistan) Students, here you can read or Download CS201 - Introduction to Programming Assignment No 1 Solution and Discussion of Semester Spring 2018. Assignment Due Date is 7 MAY, 2018. Total Marks are 20. Lecture covered in this Assignment are from Lec 1 to 6. CS201 Assignment Solution has been added. We are here to facilitate your learning and we do not appreciate the idea of copying or replicating solutions.You can also like for latest update our Facebook page, YouTube channel and follow on Google+.



Important Instructions:
Please read the following instructions carefully before submitting assignment:
It should be clear that your assignment will not get any credit if:


  • Assignment is submitted after due date.
  • Submitted assignment does not open or file is corrupt.
  • Assignment is copied (From internet/students).
  • You have to submit only .cpp file on the Assignments interface of CS201 at VULMS.
  • Assignment submitted in any other format will not be accepted and will be graded zero marks.
Assignment Objective:
To enable students to write, compile and execute a program in Dev C++. Moreover, to familiarize students with the concepts of:
  • Variables and operators 
  • Expressions in C++ 
  • Decision structures 
  • Repetition structures 
  • Break and Continue statements
Assignment Question:
Write a Program which allows the user to input an integer value for a variable name Limit.
Based on the input value, the program should perform the following tasks:

  • Check whether the value entered by the user falls within the range from 10 to 150. (10 and 150 included in the given range.) 
  • Display those numbers which are divisible by both 3 and 5 in the range from 1 up to the Limit.
  • Calculate and display the sum of those numbers which are divisible by either 3 or 5.
  • Final task will be to count and display those numbers which are not divisible by 3 or 5.
For example: 

if user enters Limit=21

Numbers which is divisible by both 3 and 5 is = 15

Numbers which are divisible by either 3 or 5= 3,5,6,9,10,12,18,20,21 (as 15 divisible by both 3 and 5, so it is not included)

Sum will be = 3+5+6+9+10+12+18+20+21= 104

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